The solubility of a gas in water is 0.11 g/L at 24.2kPa of pressure.

Question

What is the solubility when the pressure is increased to 115kPa?

Answer 1

Henry's law tells us that at constant temperature, the solubility of a gas is directly proportional to its partial pressure.

S1/P1 = S2/P2

S1 = 0.11 g/L

P1 = 24.2 kPa

S2 = ?

P2 = 115 kPa

0.11 g/L / 24.2 kPa = S2 / 115 kPa

S2 = 0.52 g / L