What percent by volume of 27 mL if methanol in 65 mL if water?

Answer 1

% by volume is mls of solute per 100 mls of solution. In this case, the solute is methanol and the solvent is water.

mls of methanol = 27 mls

mls of water = 65 mls

Total mls = 27 + 65 = 92 mls (assuming the volumes are additive)

% methanol (by volume) = 27 mls / 92 mls (x100) = 29%