determine the solution(s) to the equation x^2 +4x -5 = 0

Question

1. equation for a parabola x^2 + 4x -5 = 0
2. Does this function have a maximum or a minimum?
3. What are the coordinates of the vertex in (x,y) form?
4. What is the equation of the line of symmetry for this parabola?

Answer 1

2.   a = 1 > 0 , parabola opens up and the vertex is a minimum value of the function f(x) = x² + 4x - 5 .
3.   "x" coordinate of vertex is (-b / 2a) ,  x = -4 / 2 = -2  
      "y" coordinate of vertex is y = (-2)² + 4 (-2) - 5 = -9  
      (x,y) coordinates of vertex: (-2 , -9) 
4.    x = -2 is the equation of the line of symmetry for given parabola.

Solutions: x² + 4x - 5 = (x + 5)(x - 1) = 0 ---> x₁ = -5 and x₂ = 1