Search
Ask a question
0 0

determine the solution(s) to the equation x^2 +4x -5 = 0

  1. equation for a parabola x^2 + 4x -5 = 0
  2. Does this function have a maximum or a minimum?
  3. What are the coordinates of the vertex in (x,y) form?
  4. What is the equation of the line of symmetry for this parabola?
Tutors, please sign in to answer this question.

1 Answer

2.   a = 1 > 0 , parabola opens up and the vertex is a minimum value of the function f(x) = x2 + 4x - 5 .
3.   "x" coordinate of vertex is (-b / 2a) ,  x = -4 / 2 = -2  
      "y" coordinate of vertex is y = (-2)2 + 4 (-2) - 5 = -9  
      (x,y) coordinates of vertex: (-2 , -9) 
4.    x = -2 is the equation of the line of symmetry for given parabola.

Solutions: x2 + 4x - 5 = (x + 5)(x - 1) = 0 ---> x1 = -5 and x2 = 1