
Dayv O. answered 04/09/24
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
if tanθ=-2 and θ between 90 and 180 degrees
then cosθ=-1/√5 and sinθ=2/√5
know cos2θ=cos2θ-sin2θ
here cos2θ=(1/5)-4/5=-3/5
Brayden M.
asked 04/09/24Dayv O. answered 04/09/24
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
if tanθ=-2 and θ between 90 and 180 degrees
then cosθ=-1/√5 and sinθ=2/√5
know cos2θ=cos2θ-sin2θ
here cos2θ=(1/5)-4/5=-3/5
Tan = y/x.
-2 = -2 / 1
(-1)*(-1) + 2*2 = 5
Note: theta must be in the second quadrant because theta is between π/2 and π. y is positive here and x is negative here.
Hypotenuse (in ratio) = √5
Cos2 (1/√5) = ?
Use the cosine inverse on your calculator.
James S.
04/09/24
Dayv O.
disagree, the angle doesn't change = tan^-1(2). You are using -1/sqrt(5) as a radian (or worse degree). It is cos(theta)=-1/sqrt(5)04/10/24
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Dayv O.
if cosθ=-1/sqrt(5), then cos^2(θ)=1/504/09/24