See below Nutrient concentration

Question

How many ounces of triple superphosphate are required per 100 gallons of pure water to arrive at a concentration of one part per million ( ppm ) ? For 48% P205

Answer 1

ppm = mg / 1000 ml = 1 mg / L

1 gallon = 3.785 L (conversion factor)

100 gal = 378.5 L

For 1ppm, we will need 378.5 mg of P₂O₅ since 378.5 mg / 378.5 L = 1 mg / L = 1ppm

Now, I'm not sure if 0-48-0 means 48% P or 48% P2O5. According to the label on a package of triple super phosphate, it says it is 48% P2O5, so my calculations are going to based on that.

To get 378.5 mg of P2O5 from a mixture that is 48% P2O5, we need...

378.5 mg / 0.48 = 789 mg of the 0-48-0 material

To convert this to ounces, we have the following...

1 oz = 28350 mg

789 mg x 1 oz / 28350 mg = 0.0278 oz per 100 gallons

Note: just to clarify...this amount of 0-48-0 triple super phosphate will give you 1 ppm P2O5, not 1 ppm phosphorous. To get 1 ppm of phosphorous, you'd need about 0.0632 oz. Hope this helps.