How many moles of NaOH are needed to neutralize 1.80 grams of KHP

Answer 1

Assuming that by KHP you mean potassium hydrogen phthalate (and not potassium hydrogen phosphate), then we proceed as follows:

KHP has 1 titratable hydrogen, so the neutralization reaction would be ...

KHP + NaOH ==> NaKP + H2O where NaKP is sodium potassium phthalate

1 mol NaOH is required for each mole of KHP.

molar mass KHP = 204 g / mol

1.80 g KHP x 1 mol / 204 g x 1 mol NaOH / mol KHP = 0.00882 moles NaOH needed