What quantity of heat (in kJ) is absorbed in the process of making 0.771 mol of CF₄ from the following reaction? C (s) + 2 F₂ (g) → CF₄ (g) ∆H° = 141.3 kJ/mol

Answer 1

C(s) + 2F₂(g) ==> CF₄(g) ... ∆Hº = 141.3 kJ/mol

This tells us that for every ONE mole of CF₄ produced, 141.3 kJ of heat are absorbed.

Since we have only 0771 mols CF₄, the heat absorbed is as follows:

0.771 mols x 141.3 kJ/mol = 109 kJ (3 sig.figs.)