J.R. S. answered 03/22/24
Ph.D. University Professor with 10+ years Tutoring Experience
π = iMRT
π = osmotic pressure = 115 mm Hg x 1 atm / 760 mm Hg = 0.151 atm
i = van't Hoff factor = 1 for C6H12O6 (glucose) which is a non electrolyte
M = molarity = ?
R = gas constant = 0.0821 Latm/Kmol
T = temperature in Kelvin = 19C + 273 = 292K
Solving for M (molarity), we have ...
M = π / (i)(R)(T)
M = 0.151 atm / (1)(0.0821 Latm/Kmol)(292K)
M = 0.00630 M = 0.006 M (3 decimal places)