what volume in liters of CH3OH gas forms when 3.20 L of H2 gas are completely reacted at STP according to the following chemical reaction?

Question

Remember 1 mol of an ideal gas has a volume of 22.4 L at STP.

CO(g)+2H2(g)->CH3OH(g)

please show equation not just the answer!

Answer 1

CO(g) + 2H₂(g) ==> CH₃OH .. balanced equation

According to the stoichiometry of the balanced equation, TWO moles H2 form ONE mole CH₃OH. Since the reaction is at STP (standard temperature and pressure), it is also true that TWO liters of H₂ form ONE liter of CH₃OH. Using this relationship, we can solve the problem as follows:

3.20 L H₂ x 1 L CH₃OH / 2 L H₂ = 1.60 L of CH₃OH

If you want to solve this using the hint provided, that 1 mole of gas @ STP = 22.4 L, you can proceed as follows:

From balanced equation, 2 moles H₂ = 1 mole CH₃OH

3.20 L H₂ x 1 mol H₂ / 22.4 L = 0.143 moles H₂

0.143 mols H₂ x 1 mole CH₃OH / 2 mols H₂ = 0.0714 moles CH₃OH formed

0.0714 moles CH₃OH x 22.4 L / mole = 1.60 L CH₃OH