If 0.178 mol of zinc reacts with a excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction

Answer 1

2 Zn(s) + Pb(SO₄)₂ ==> 2 ZnSO₄ + Pb(s) .. balanced equation

molar mass ZnSO₄ = 161.4 g / mol

mass ZnSO4 formed = 0.178 mol Zn x 2 mol ZnSO₄ / 2 mol Zn x 1 61 g / mol = 28.7 g ZnSO₄ (3 sig.figs.)