J.R. S. answered 03/05/24
Ph.D. University Professor with 10+ years Tutoring Experience
Moles sugar = 39 g / 180 g/mol = 0.217 mol
Volume of solution = 355 ml = 0.355 L
Mass of solution = 355 ml x 1.026 g/ml = 364 g
Mass of water = 364 g - 39 g = 325 g = 0.325 kg
Moles Water = 325 g /18 g/mol = 18 mol
Molarity = mol/L = 0.217 mol/ 0.355 L =0.61 M
Molality = mol/kg water = 0.217/0.325 = 0.67 m
Mole fraction = mol sugar/total mols = 0.217/0.217 + 18 = 0.011
Percent sugar by mass = 39 g/364 g (x100) = 11%