2H2S + 3O2 -> 2SO2 +2H2O How many grams of water can you make from 26 grams of O2 assuming Hydrogen Sulfide is in excess?

Answer 1

2H2S + 3O2 -> 2SO2 + 2H2O 

Since H2S is in excess, we can determine the amount of water formed by using the mole ratio of O2 to H2O, which in the balanced equation is 3:2

moles O2 = 26 g O2 x 1 mol O2 / 32 g = 0.8125 moles O2

moles H2O formed = 0.8125 mol O2 x 2 mol H2O / 3 mol O2 = 0.542 moles H2O

grams H2O formed = 0.542 moles x 18 g/mol = 9.76 g = 9.8 g H2O formed (2 sig figs)