Energy Transfer

Question

What is the change in temperature if 90 grams of steam releases 945 calories of energy

Answer 1

The specific heat for steam is 0.48 cal/g^o

q = mcΔT

945 cal = (90 g)(0.45 cal/g^o)(ΔT)

ΔT = 23.3^o= change in temperature

This calculation assumes the temperature of the stream was initially greater than 123.3^o