Dillution Chemical Reactions

Question

A chemist must prepare 275.mL of 92.0μM aqueous mercury(II) iodide HgI2 working solution. She'll do this by pouring out some 94.8μmolL aqueous mercury(II) iodide stock solution into a graduated cylinder and diluting it with distilled water.

Calculate the volume in mL of the mercury(II) iodide stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits.

Answer 1

V1M1 = V2M2

V1 = initial volume = ?

M1 = initial molarity = 94.8 uM

V2 = final volume = 275 ml

M2 = final molarity = 92.0 uM

(V1)(94.8) = (275)(92.0)

V1 = 266.9 ml = 267 mls (3 sig figs)