Na2CO3 + Ca(NO3)2 → CaCO3 + 2NaNO3 what mass of calcium nitrate in grams is needed to produce 5.69mol of sodium nitrate?

Answer 1

From the balanced equation you can see that it takes 1 MOLE of calcium nitrate, Ca(NO3)2, to produce 2 MOLES of sodium nitrate, NaNO3. Using this ratio, we can set up the problem as follows:

5.69 mol NaNO3 x 1 mol Ca(NO3)2 / 2 mol NaNO3 = 2.845 moles Ca(NO3)2 needed

Now we just use the molar mass of Ca(NO3)2 to convert to grams.

2.845 mols x 164 g/mol = 467 g