Need help with chemistry problem.

Question

the NaOH solution is standardized with KHP in this lab. If about 0.8 grams of KHP (MW=204.22 g/mol) is titrated with approximately 0.1 M NaOH what is the approximate volume of NaOH required to reach the endpoint?

Answer 1

KHP + NaOH ==> NaKP + H2O .. balanced eq

~moles KHP = 0.8 g x1 mole/204 g = 0.0039 mol

~moles NaOH needed = 0.0039 moles

~volume NaOH = 0.0039 mol x 1L/0.1 mol = 0.039 L = ~39 mls

Answer 2

Approximately 39.16 mL of NaOH is required to reach the endpoint.

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