Ideal Gas Law Problem

Question

What pressure would be exerted by 12 moles of gas at 330 C and a volume of 600 cm3?

Answer 1

Again, use the Ideal gas law:

PV = nRT

P = pressure in atm = ?

V = volume in liters = 600 cm³ x 1 L / 1000 cm³ = 0.600 L

n = moles of gas = 12 mols

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = 330C + 273 = 603K

Solving for P, we have...

P =nRT / V = (12 mols)(0.0821 Latm/Kmol)(603K) / 0.600 L

P = 990 atm (2 significant figures)