Compare the solutions of 0.50 M NaCl and 0.50 M sucrose (i=1) with the following parameters. a. Which solution has the higher boiling point. b. Which solution has the higher freezing/melting point.

Answer 1

0.50 M NaCl will produce 0.50 M Na+ and 0.50 M Cl-. So, 2 particles each at 0.50M

0.50 M sucrose will produce only 1 particle at 0.50 M. Sucrose is a non electrolyte.

So, since both boiling point and freezing points are colligative properties,

a) the 0.50 M NaCl will have the higher boiling point, and

b) the 0.50 M NaCl will have the lower freezing point/melting point