How many representative particles of NF3 are formed when 30 L of N2 at STP is consumed in the following reaction? N2 + 2F3 ------> 2NF3

Answer 1

N₂ + 2F₃ ==> 2NF₃ .. balanced equation

At STP, 1 mole of an ideal gas = 22.4 L. Given this relationship, we can first find the moles of N₂ used:

moles N₂ = 30 L N₂ x 1 mole / 22.4 L = 1.34 moles N₂

Next, using the stoichiometry of the balanced equation, we can determine the moles of NF₃ formed:

moles NF₃ = 1.34 mols N₂ x 2 moles NF₃ / 1 mole N₂ = 2.68 moles NF₃ formed

Finally, using Avogadro's number, we can find the number of particles (molecules) of NF₃:

2.68 moles NF₃ x 6.02x10²³ particles / mole = 1.6x10²⁴ particles (molecules) of NF₃