Kate H.
asked 01/28/24Solve by elimination
Solve by elimination:
Y=x^2+4x-24,
Y=6x+11
2 Answers By Expert Tutors
Peter R. answered 01/28/24
Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
Subtract the two equations:
y = x2 +4x - 24
y = 6x + 11
0 = x2 - 2x - 35 (factor)
0 = (x -7)(x + 5)
x = 7; x = -5
solve for y:
y = 6(7) + 11; y = 53
y = 6(-5) + 11; y = -19
Raymond B. answered 01/28/24
Math, microeconomics or criminal justice
x^2 +4x-24= 6x+11
x^2-2x -35=0
(x-7)(x+5)=0
x =-5, 7
y=-19, 53
(x,y)= (-5,-19) and (7, 53)
check the answers
(-5)^2 +4(-5)-24 = 25-44=-19
6(-5)+11 =-30+11 =-19
7^2 +4(7)-24 =49+28-24=53
6(7)+11 = 42+11 =53
or use a graphing calculator and
see where the parabola intersects the line
Kate H.
I need to see it by elimination, not substitution.01/28/24
Raymond B.
they are virtually the same. you have an instructor who is pathetically hairsplitting if s/he thinks there is a real difference01/28/24
Kate H.
Haha, thank you01/28/24
Kate H.
I can see the "elimination" now01/28/24
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Kate H.
I need to see this by elimination, not substitution.01/28/24