What are the probabilities of these M&M

Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible)

a. Compute the probability that a randomly selected peanut M&M is not green.

b. Compute the probability that a randomly selected peanut M&M is orange or blue.

c. Compute the probability that two randomly selected peanut M&M’s are both brown.

d. If you randomly select four peanut M&M’s, compute that probability that none of them are blue.

e. If you randomly select four peanut M&M’s, compute that probability that at least one of them is blue.

 

Answer 1

P(not green)= 1-.15=.85= 85.0000%

P(orange or blue)= ,23 +,23 = .46= 46.0000%

P(both brown)= .12^2 =.0144= 1.4400%

P(4 not blue)= (1-.23)^4= .77^4=.35153041= 35.1530%

P(at least one blue)= 1-P(none are blue)= 1- .77^4 =.64846959= 64.8470%