For the first two, you can use the formulas μ = (b-a)/2 and σ = (b-a)/√12. In this case
(a) mean = (53-1)/2 = 26
(b) s.d. = (53-51)/√12 = 15.0111
c) Because this is a continuous distribution, the probability of being at any exact moment is 0.
d) Probability between 2 times is the difference between those two times and the endpoints: p(14<x<24) = (24-14)/(53-1) = 10/52 = 5/26.
e) After week 21 would be between weeks 21 and 53: P(x>21) = (53-21)/52 = 32/52 = 8/13.
f) For given probability, you're just changing the endpoints in the denominator: P(x>20|x<42) = (42-20)/42-1) = 22/41.
g) Simply solve (x-1)/52 = 0.53. x-1 = 27.56. x = 28.56.
h) Same thing, but it equals 0.75: (x-1)/52 = 0.75. x-1 = 39. x=40.