Inactive Tutor answered 12/10/23
Tutor
New to Wyzant
P(x=0)= .6^9
P(x=1) =9(.4)(.6)^8
P(x=2)=36(.4^2)(.6)^7
P(x-3) = 9C3(.4^3)(.6^6)=84(.064)(.6^6)
add them up to get P(x</=3)
Kristie S.
asked 12/10/23n=9, p=0.4, x<_3
The probability of x<_3 successes is ?
Inactive Tutor answered 12/10/23
P(x=0)= .6^9
P(x=1) =9(.4)(.6)^8
P(x=2)=36(.4^2)(.6)^7
P(x-3) = 9C3(.4^3)(.6^6)=84(.064)(.6^6)
add them up to get P(x</=3)
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