Inactive Tutor answered 12/10/23
P(D)=.004
false neg = 5%
false pos = 2%
+ - total
D .38 .02 .4
~D 1.992 97.608 99.6
2.372 97.628 100
P(+)= 2.372%
P(D/=)=.38/2.372 = .1602 = 16.020%
if you really meant 0.4% and not 4%
Salma H.
asked 12/09/23A certain disease has an incidence rate of 0.4%. If the false negative rate is 5% and the false positive rate is 2%, compute the probability that a person who tests positive actually has the disease.
Give your answer accurate to at least 3 decimal places _______
Inactive Tutor answered 12/10/23
P(D)=.004
false neg = 5%
false pos = 2%
+ - total
D .38 .02 .4
~D 1.992 97.608 99.6
2.372 97.628 100
P(+)= 2.372%
P(D/=)=.38/2.372 = .1602 = 16.020%
if you really meant 0.4% and not 4%
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