
Martin C. answered 12/06/23
I'm Good at Walking Students Through Geometric Proofs
This problem can be solved by realizing that the radius of the small circle is perpendicular to the tangent to it at that point, which is a chord of the larger circle. Hence, a right triangle is formed with the radius of the large circle being the hypotenuse, the radius of the small circle being one leg, and HALF the tangent/chord being the other leg. Since the radii of the two circles are given as 4 and 8 centimeters, the half-segment that is the other leg must have a length of 4√3 centimeters, and thus the whole segment has a length of 8√3 centimeters.