What percentage of the molecules are at or above the activation energy at 500.0 K?

Question

The activation energy for a particular reaction is Ea=16.00kj

Answer 1

Fraction of molecules above activation energy = e^(-Ea/RT)

Ea = energy of activation = 16.00 kJ x 1000 J / kJ = 16,000 kJ

R = gas constant = 8.314 J/molK

T = temperature in Kelvin = 500K

Fraction of molecules above activation energy = e^{(-16000 J / 8.314 J/Kmol * 500K)}

Fraction of molecules above activation energy = 0.0213

Converting to % we have 2.13% of the molecules above activation energy.