Balance the nuclear equation by giving he mass number, atomic number, and element symbol for the missing species.

Question

²⁷Al+⁴He---->+¹₀n. (supposed to be 1 over 0)

Answer 1

We need to include the atomic numbers for Al and He which are 13 and 2, respectively.

²⁷₁₃Al + ⁴₂He ==> ¹₀n + X where X

Since the atomic masses and atomic numbers (protons) must be equal on both sides, we can find these values for X and then look in the periodic table to identify X:

²⁷₁₃Al + ⁴₂He ==> ¹₀n + ³⁰₁₅X and since X has 15 protons is must be phosphorous (P)

²⁷₁₃Al + ⁴₂He ==> ¹₀n + ³⁰₁₅P