Calculate the cell potential (Ecell) for the following lead concentration cell at 298 K.

Question

Calculate the cell potential (E_cell) for the following lead concentration cell at 298 K.

[Pb²⁺] = 0.00100 M   [ Pb²⁺] = 2.75 M

Answer 1

Eº for a concentration cell = 0

Ecell = Eº - 0.0592/n log Q at 25ºC or 298K This is the Nernst equation @25ºC/298K

Pb | Pb²⁺(0.001M) || Pb²⁺(2.75M) | Pb

Q = 0.001 / 2.75 = 3.64x10^-4

Plugging into Nernst equation and solving for Ecell, we have...

Ecell = 0 - 0.0592/2 log 3.64x10^-4

Ecell = -0.0296 x -3.44

Ecell = 0.102 V