Algebra 1 question

Question

the height of the triangle is 4 inches shorter than the base the are of the triangle is 198 square inches find the dimensions of the triangle. find the dimensions.

Answer 1

Area = base×height/2 = bh/2 = b(b-4)/2 = 198

b²-4b -396 = 0

(b-22)(b+18) = 0

b=22, -18 Since this is a dimension, use 22.

b=22

h = b-4 = 18

Answer 2

Height = Base - 4

Area = 1/2( Base* Height) = 198

198 = 1/2 (B ) (B-4)

396 = B(B-4)

B²-4B -396 =0

Solve for B

B = 22 0r -18

ignore -18

Height = Base - 4 = 22-4 = 18 inch

Base =22 inch