J.R. S. answered 11/30/23
Ph.D. University Professor with 10+ years Tutoring Experience
The d subshell can have 10 electrons, 2 in each of the 5 d orbitals.
5dz2 = 2 electrons
1d = 0 electrons because n = 1, no d orbitals
5 d = 10 electrons
6 d = 10 electrons
The p subshell can have 6 electrons, 2 in each of the 3 p orbitals
7p = 6 electrons
For n = 3, we have 3s2 3p6 3d10 = 18 electrons