Standard enthalpy change

Question

Calculate the standard enthalpy change for the reaction at 25 °C. Standard enthalpy of formation values can be found in this list of thermodynamic properties.

H2O(g)+ C(graphite)(s) —> H2(g)+CO(g)

Answer 1

Looking up ∆Hº_f on Wikipedia...

H₂O(g) = -241.8 kJ/mole

C(graphite) = 0

H₂(g) = 0

CO(g) = -110.5 kJ/mole

∆Hº_rxn = ∑∆H_products - ∑∆H_reactants

∆Hº_rxn = -110.5 - (-241.8)

∆Hº_rxn = = 131.3 kJ/mole