Inactive Tutor answered 11/24/23
z=1.282 for 80%
use z tables or a z calculator
Margin Of Error=
MOE = z(sd)/sqr(n) = 1.282(20)/sqr(10)
=25.64/sqr10
Confidence Interval = mean plus or minus MOE
CI=49+/-25.64/sq10= about 49+/-8.1
=(40.9, 57.1)
Mekhia M.
asked 11/24/23In a survey, 10 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $49 and standard deviation of $20. Construct a confidence interval at a 80% confidence level.
Give your answers to one decimal place.
Inactive Tutor answered 11/24/23
z=1.282 for 80%
use z tables or a z calculator
Margin Of Error=
MOE = z(sd)/sqr(n) = 1.282(20)/sqr(10)
=25.64/sqr10
Confidence Interval = mean plus or minus MOE
CI=49+/-25.64/sq10= about 49+/-8.1
=(40.9, 57.1)
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