J.R. S. answered 11/20/23
Ph.D. University Professor with 10+ years Tutoring Experience
Use the Henderson Hasselbalch equation:
pH = pKa + log [NaC7H5O2] / [HC7H5O2]
pKa = -log Ka = -log 6.54x10-5 = 4.18
pH = 4.18 + log [0.565] / [0.0876]
pH = 4.18 + log 6.45
pH = 4.18 + 0.81
pH = 4.99