Calculate the size of electric current that must flow.

Question

Suppose 500. mmol of electrons must be transported from one side of an electrochemical cell to another in 60.0 minutes. Calculate the size of electric current that must flow.

Be sure your answer has the correct unit symbol and round your answer to 

3 significant digits. 

Answer 1

500.0 mmoles electrons x 1 mole / 1000 mmoles = 0.5000 moles of electrons

1 mole electrons = 96,500 C (coulombs)

Q = IT

Q = 96.500 C / mole e- x 0.500 mols e- = 48.250 C

I = ?

T = time = 60.0 min x 60 sec / min = 3600 sec

Solving for I, we have..

I = Q / T = 48,250 C / 3600 sec

I = 13.4 C/sec = 13.4 A (amps)