J.R. S. answered 11/17/23
Ph.D. University Professor with 10+ years Tutoring Experience
For the reaction Cd2+(aq) + Mg(s) ==> Mg2+(aq) + Cd(s), the Cd2+ is being reduced (cathode) and the Mg(s) is being oxidized (anode).
A. Anode equation: Mg(s) ==> Mg2+(aq) + 2e-
B. Cathode equation: Cd2+(aq) + 2e- ==> Cd(s)
C. Cell equation: Cd2+(aq) + Mg(s) ==> Mg2+(aq) + Cd(s)