Pieces of cadmium and tin are placed in a solution in which [Cd2+] = [Sn2+] = 1.00 M. What is Ecell?

Question

The standard reduction potentials for the species in the reaction are shown below:

Sn²⁺(aq) + 2e^- --> Sn(s) E (red) = -.136V

Cd²⁺(aq) + 2e^- --> Cd(s) E (red) = -0.403

Answer 1

Sn²⁺(aq) + 2e^- --> Sn(s) E (red) = -.136V ... represents the cathode (reduction)

Cd²⁺(aq) + 2e^- --> Cd(s) E (red) = -0.403 ... represents the anode (oxidation)

Eºcell = -0.136 + 0.403

Eºcell = 0.267 V

Overall reaction:

Sn²⁺(aq) + Cd(s) ==> Cd²⁺(aq) + Sn(s) ... Eºcell = 0.267V