J.R. S. answered 11/16/23
Ph.D. University Professor with 10+ years Tutoring Experience
PbO2(s) + HSO4-(aq) + 3H++ 2e- --> PbSO4(s) + 2H2O (l) (reduction @ cathode)
Pb(s) + HSO4-(aq) --> PbSO4(s) + H+(aq) + 2e- (oxidation @ anode)
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PbO2(s) + 2HSO4-(aq) + 2H+ + Pb(s) --> 2PbSO4(s) + 2H2O (l) ... net ionic equation