question is below in the description

Question

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.80 MJ of energy (in the form of heat) if the temperature of the sodium is not increase by more than 10.0 degrees Celsius? Use Cp=30.8J/(K*mol) for Na(l) at 500K.

Answer 1

q = mC∆T

q = heat = 1.80 MJ

m = mass = ?

C = specific heat = 30.8 J/molº x 1 mol / 22.99 g = 1.34 J/gº = 1.34x10^-6 MJ/gº

∆T = 10º

Solving for mass...

m = q / C∆T

m = 1.80 MJ / 1.34x10^-6 MJ/gº x 10

m = 134328 g = 134 kg