Balance the redox reaction by inserting the appropriate coefficients

Question

Balance the redox reaction by inserting the appropriate coefficients

redox reaction:Fe³⁺ +NO₂^- +H₂O---->Fe²⁺ +H⁺ + NO₃^-

Answer 1

2Fe³⁺ + 1NO₂^- + 1H₂O ==> 2Fe²⁺ + 2H⁺ + 1NO₃^-

Oxidation half reaction:

NO₂^- ===> NO₃^-

NO₂^- + H₂O ===> NO₃^- .. balanced for N and O

NO₂^- + H₂O ===> NO₃^- + 2H⁺ .. balanced for N and O and H

NO₂^- + H₂O + ===> NO₃^- + 2H⁺ + 2e- .. balanced for N and O and H and charge = BALANCED EQ.

Reduction half reaction:

Fe³⁺ ==> Fe²⁺

Fe³⁺ + e- ==> Fe²⁺ .. balanced for Fe and charge = BALANCE EQ.

Multiply reduction reaction by 2 to equalize electrons and add to the oxidation half reaction:

NO₂^- + H₂O + ===> NO₃^- + 2H⁺ + 2e-

2Fe³⁺ + 2e- ==> 2Fe²⁺

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NO₂^- + 2Fe³⁺ + H₂O ==> NO₃^- + 2Fe²⁺ + 2H⁺ ... BALANCED REDOX EQUATION