J.R. S. answered 11/11/23
Ph.D. University Professor with 10+ years Tutoring Experience
Cu(s) + 2AuCl(aq) ==> CuCl2(aq) + 2Au(s)
Cu(s) goes from oxidation number 0 to oxidation number 2+ in CuCl2. It has been oxidized.
Au in AuCl goes from oxidation number 1+ to zero in Au(s). It has been reduced.
Oxidation half reaction: Cu(s) ===> Cu2+(aq) + 2e-
Reduction half reaction: Au+(aq) + e- ===> Au(s)
(NOTE: the reduction half reaction is NOT balanced. Multiply by 2 to equalize the electrons)
BALANCED REACTIONS:
Oxidation half reaction: Cu(s) ===> Cu2+(aq) + 2e-
Reduction half reaction: 2Au+(aq) + 2e- ===> 2Au(s)
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OVERALL RXN: Cu(s) + 2Au+(aq) ===> Cu2+(aq) + 2Au(s)