Raymond B. answered 11/11/23
Math, microeconomics or criminal justice
Pr(at least one green) on 2 draws randomly from 7 green and 5 not green = 1-Pr(no green)
= 1- 5/12)(5/11) = 1- 25/132 = (132-25)/132 = 107/132
Maria P.
asked 11/11/23Suppose that you have 7 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards without replacement.
G1 = the first card drawn is green
G2 = the second card drawn is green
Raymond B. answered 11/11/23
Math, microeconomics or criminal justice
Pr(at least one green) on 2 draws randomly from 7 green and 5 not green = 1-Pr(no green)
= 1- 5/12)(5/11) = 1- 25/132 = (132-25)/132 = 107/132
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