Calculate the molar solubility, s, of this compound.

Question

The K_sp of tin (II) hydroxide, Sn(OH)₂, is 5.45 x 10^-27 .Calculate the molar solubility, s, of this compound.

s= ?M

Answer 1

Sn(OH)₂(s) <==> Sn²⁺(aq) + 2OH-(aq)

Ksp = [Sn²⁺][OH-]²

Let [Sn²⁺] = s

Then, [OH-] = 2s

Plugging these values into the Ksp expression, we have...

Ksp = 5.45x10^-27 = (s)(2s)²

5.45x10^-27 = 4s³

s³ = 1.363x10^-27

s = 1.11x10^-9 = molar solubility of Sn(OH)₂