What is the concentration of S2- in equilibrium with MnS(s) (Ksp=4.6x10-14) and 0.062 M Mn2+?

Question

What is the concentration of S^2- in equilibrium with MnS(s) (K_sp=4.6x10^-14) and 0.062 M Mn²⁺?

[S^2-]=? M

Answer 1

MnS(s) <==> Mn²⁺(aq) + S^2-(aq) .. equilibrium between solid MnS and the Mn²⁺ and S^2- aqueous ions

Ksp = [Mn²⁺][S^2-]

4.6x10^-14 = [0.062][S^2-]

[S^2-] = 7.4x10^-13 M