J.R. S. answered 11/04/23
Ph.D. University Professor with 10+ years Tutoring Experience
H2SO4 + 2NaOH ==> Na2SO4 + 2H2O .. balanced equation
moles NaOH needed = 47.73 ml x 1 L / 1000 ml x 0.1459 mol / L = 6.964x10-3 mols NaOH
moles H2SO4 present = 6.964x10-3 mols NaOH x 1 mol H2SO4 / 2 mol NaOH = 3.482x10-3 mols
concentration of H2SO4 = 3.482x10-3 mols / 25.00 mls x 1000 ml / L = 0.1393 M