J.R. S. answered 11/04/23
Ph.D. University Professor with 10+ years Tutoring Experience
a). pH of pure water depends on the temperature. At 25ºC pH of pure water = 7. The volume (1.000 L) or any other volume does not affect the pH.
b). Adding a strong acid to unbuffered water will result in a large change in pH. The pH will fall drastically.
c). If 200.00 ml of 1.000 M nitric acid (HNO3, a strong acid), is added to 1.000 L of pure water, the pH can be calculated as follows:
moles HNO3 added = 200.00 ml x 1 L / 1000 ml x 1.000 mol / L = 0.2000 mols HNO3 added
Since it is a strong acid, this means 0.2000 moles H+ have been added
Total volume is now 1.2000 L, so [H+] = 0.2000 mol / 1.200 L = 0.1667 M
pH = -log [H+]
pH = -log 0.1667
pH = 0.778