How many moles of NiCl2 N i C l 2 can be formed in the reaction of 8.00 mol m o l of Ni N i and 16.0 mol m o l of HCl H C l ?

Answer 1

Ni(s) + 2HCl(aq) ==> NiCl₂(aq) + H₂(g) .. balanced equation

Find limiting reactant:

Ni: 8.00 mol / 1 = 8

HCl: 16.0 mol /2 = 8

Neither reactant is limiting as they are present in stoichiometric amounts

8.00 mols Ni will produce 8.00 mols NiCl₂

16.00 mols HCl will produce 8.00 mols NiCl₂