J.R. S. answered 11/04/23
Ph.D. University Professor with 10+ years Tutoring Experience
The original buffer solution contains a weak base, NH3 and its conjugate acid, NH4+. Addition of the acid, HNO3, will react with the base, NH3 to produce NH4+
Initial moles NH3 = 275 ml x 1 L / 1000 ml x 0.240 mol / L = 0.066 mols
Initial moles NH4+ = 275 ml x 1 L / 1000 ml x 0.240 mol / L = 0.066 mols
Initial moles HNO3 = 1.90 ml x 1 L / 1000 ml x 6.00 mol / L = 0.0114 mols
NH3 + HNO3 ==> NH4+ + NO3-
0.066.......0.0114..........0.066...............Initial
-0.0114...-0.0114........+0.0114............Change
0.0515..........0...........0.0774.............Equilibrium
Final volume = 275 ml + 1.90 ml = 276.90 ml = 0.2769 L
Final [NH3] = 0.0515 mol / 0.2769 L = 0.186 M
Final [NH4+] = 0.0774 mol / 0.2769 L = 0.280 M