What would be the molar mass of a gas with pressure 22336.4 mm of Hg; 25.5L at 59 degrees C with a mass of 880g? Gas constant is 0.0821 L.atm/mol.K

Answer 1

Ideal gas law: PV = nRT

P = pressure = 22336.4 mm Hg x 1 atm / 760 mm Hg = 29.39 atm

V = volume in L = 25.5 L

n = moles of gas = ?

R = 0.0821 Latm/Kmol

T = temperature in Kelvin = 59ºC + 273 = 332K

Solve for n (moles):

n = PV/RT = (29.39)(25.5) / (0.0821)(332)

n = 27.49 moles of gas

Molar mass = g / mole = 880 g / 27.49 moles

Molar mass = 32.0 (could be oxygen gas)