J.R. S. answered 10/27/23
Ph.D. University Professor with 10+ years Tutoring Experience
The system described represents a buffer system containing a weak acid (HCHO2) and the conjugate base (NaCHO2). For this calculation, we can use the Henderson Hasselbalch equation:
pH = pKa + log [conj.base] / [acid]
We are given the pH, pKa and [NaCHO2]. Solve for [HCHO2]
3.89 = 3.74 + log (0.735/x)
0.15 = log 0.735/x
1.41 = 0.735/x
x = 0.521 M = [HCHO2]