J.R. S. answered 10/26/23
Ph.D. University Professor with 10+ years Tutoring Experience
2 HNO3(aq) + Ba(OH)2 (aq) ==> 2 H2O (I) + Ba(NO3)2 (aq) .. balanced reaction
mols Ba(OH)2 used = 37.9 ml x 1 L / 1000 ml x 0.250 mol / L = 9.475x10-3 moles
mols HNO3 present = 9.475x10-3 mol Ba(OH)2 x 2 mol HNO3 / mol Ba(NO3)2 = 0.01895 mol HNO3
Concentration HNO3 = 0.01895 mols / 0.120 L = 0.158 M (3 sig. figs.)